Here is a right triangle, split along the altitude to the hypotenuse.
This creates three similar triangles: ABD, CAD, and CBA. Using similarity, you can show
and also
which is all you need to show that
The neat part is that it requires no argument about areas at all.
Essays on education, debate, and math instruction; neat math problems; and whatever else I get around to.
Showing posts with label Pythagorean theorem. Show all posts
Showing posts with label Pythagorean theorem. Show all posts
Tuesday, December 10, 2013
Monday, December 9, 2013
Looking for Pythagorean pair-doubles
In teaching a geometry course, I find that I frequently need a Pythagorean triple. A Pythagorean triple, of course, is three whole numbers that satisfy the Pythagorean theorem to make a right triangle: 3, 4, 5, or 7, 40, 41.
But even more frequently, I find I need a Pythagorean pair-double: two sets of whole number-length legs with the same hypotenuse. For example, 5, 5 and 1, 7 are a pair-double, since both have the same hypotenuse. In this way, I can make an isosceles triangle that requires a little work to prove it isosceles.
Labels:
geometry,
Pythagorean theorem,
Pythagorean triples
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